Question

C语言怎么样用二分法求方程的解

用二分法求2X^3-4X^2+3X-6=0在(-10,10)之间的根~~~要求用WIN-TC

Answer 1

x1,x2请输入-10，10
#include <stdio.h>
#include <math.h>
void main()
{
float x0,x1,x2,f0,f1,f2;
do
{
printf("please enter x1 & x2:\n");
scanf("%f,%f",&x1,&x2);
f1=((2*x1-4)*x1+3)*x1-6;
f2=((2*x2-4)*x2+3)*x2-6;
}
while ((f1*f2)>0);
do
{
x0=(x1+x2)/2;
f0=((2*x0-4)*x0+3)*x0-6;
if ((f0*f1)<0)
{
x2=x0;
f2=f0;
}
else
{
x1=x0;
f1=f0;
}
}
while(fabs(f0)>=1e-5);
printf("the root of equation is :%f\n",x0);
}

Answer 2

x1,x2请输入-10，10
#include
<stdio.h>
#include
<math.h>
void
main()
{
float
x0,x1,x2,f0,f1,f2;
do
{
printf("please
enter
x1
&
x2:\n");
scanf("%f,%f",&x1,&x2);
f1=((2*x1-4)*x1+3)*x1-6;
f2=((2*x2-4)*x2+3)*x2-6;
}
while
((f1*f2)>0);
do
{
x0=(x1+x2)/2;
f0=((2*x0-4)*x0+3)*x0-6;
if
((f0*f1)<0)
{
x2=x0;
f2=f0;
}
else
{
x1=x0;
f1=f0;
}
}
while(fabs(f0)>=1e-5);
printf("the
root
of
equation
is
:%f\n",x0);
}