MATLAB难题:如何把一个复杂的含符号表达式按按一定精度化简。

不是simple,是要按一定精度把分式化为小数。y=1/2115999668407111*(5070602400912917605986812821504-4477454... 不是simple,是要按一定精度把分式化为小数。
y =1/2115999668407111*(5070602400912917605986812821504-4477454596699003705844035366321*z1^2/(((z1-19/20+x-3/10*(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)/(19/20-x)/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*cos((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)+((19/20-x)^2/(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)+3/10/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*(36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)^2+((z1-19/20+x-3/10*(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)/(19/20-x)/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*sin((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)-((19/20-x)^2/(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)+3/10/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*cos((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1))^2))^(1/2)/z1*(((z1-19/20+x-3/10*(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)/(19/20-x)/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*cos((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)+((19/20-x)^2/(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)+3/10/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*(36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)^2+((z1-19/20+x-3/10*(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)/(19/20-x)/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*sin((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1)-((19/20-x)^2/(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)+3/10/(1+(23509722736682911/9007199254740992-6186769141232345/2251799813685248*x)^2/(19/20-x)^2)^(1/2))*cos((36573973662147359/9007199254740992-6186769141232345/2251799813685248*x)/z1))^2)^(1/2)-1639176211415221/4503599627370496+z2/z1*(tan(2115999668407111/2251799813685248*z2/(z2+2-2*x))-1639176211415221/4503599627370496)
展开
 我来答
hallowwar
2009-12-17 · TA获得超过553个赞
知道小有建树答主
回答量:630
采纳率:0%
帮助的人:411万
展开全部
>> digits(3)
>> vpa(y)

ans =

.473e-15*(.507e31-.448e31*z1^2/(((z1-.950+x-1.*(.783-.824*x)/(.950-1.*x)/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*cos((4.06-2.75*x)/z1)+((.950-1.*x)^2/(2.61-2.75*x)+.300/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*(4.06-2.75*x)/z1)^2+((z1-.950+x-1.*(.783-.824*x)/(.950-1.*x)/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*sin((4.06-2.75*x)/z1)-1.*((.950-1.*x)^2/(2.61-2.75*x)+.300/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*cos((4.06-2.75*x)/z1))^2))^(1/2)/z1*(((z1-.950+x-1.*(.783-.824*x)/(.950-1.*x)/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*cos((4.06-2.75*x)/z1)+((.950-1.*x)^2/(2.61-2.75*x)+.300/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*(4.06-2.75*x)/z1)^2+((z1-.950+x-1.*(.783-.824*x)/(.950-1.*x)/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*sin((4.06-2.75*x)/z1)-1.*((.950-1.*x)^2/(2.61-2.75*x)+.300/(1.+(2.61-2.75*x)^2/(.950-1.*x)^2)^(1/2))*cos((4.06-2.75*x)/z1))^2)^(1/2)-.364+z2/z1*(tan(.940*z2/(z2+2.-2.*x))-.364)
本回答被提问者采纳
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
推荐律师服务: 若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询

为你推荐:

下载百度知道APP,抢鲜体验
使用百度知道APP,立即抢鲜体验。你的手机镜头里或许有别人想知道的答案。
扫描二维码下载
×

类别

我们会通过消息、邮箱等方式尽快将举报结果通知您。

说明

0/200

提交
取消

辅 助

模 式