Question

怎么给int **的二维数组赋值

int i=0;int j=0;
int maze1[10][10]={
{1,1,1,1,1,1,1,1,1,1},
{1,0,0,0,1,1,0,1,0,1},
{1,1,1,0,1,0,0,0,0,1},
{1,0,1,0,0,1,1,0,1,1},
{1,0,1,1,0,0,0,1,1,1},
{1,0,0,0,1,0,0,1,0,1},
{1,0,0,1,0,1,0,0,1,1},
{1,1,1,0,0,1,0,0,0,1},
{1,0,0,0,1,0,0,1,0,1},
{1,1,1,1,1,1,1,1,1,1}};

int *maze2;
maze2=new int [10];
for(i=0;i<10;i++) //apply for eacn indicator
{
maze[i]=new int[10];
}

for(i=0;i<10;i++){
for(j=0;j<10;j++)
{
*maze2[i][j]==&maze1[i][j];
}
}

maze=new int *[10]; //apply for an indicator
for(i=0;i<10;i++) //apply for eacn indicator
{
maze[i]=new int[10];
}

for(i=0;i<10;i++){
for(j=0;j<10;j++)
{**maze[i][j]=&maze2[i][j];}
}
这样赋值有什么问题

Answer 1

int maze1[10][10]={
{1,1,1,1,1,1,1,1,1,1},
{1,0,0,0,1,1,0,1,0,1},
{1,1,1,0,1,0,0,0,0,1},
{1,0,1,0,0,1,1,0,1,1},
{1,0,1,1,0,0,0,1,1,1},
{1,0,0,0,1,0,0,1,0,1},
{1,0,0,1,0,1,0,0,1,1},
{1,1,1,0,0,1,0,0,0,1},
{1,0,0,0,1,0,0,1,0,1},
{1,1,1,1,1,1,1,1,1,1}};

改为：
int maze1[10][10]={
1,1,1,1,1,1,1,1,1,1,
1,0,0,0,1,1,0,1,0,1,
1,1,1,0,1,0,0,0,0,1,
1,0,1,0,0,1,1,0,1,1,
1,0,1,1,0,0,0,1,1,1,
1,0,0,0,1,0,0,1,0,1,
1,0,0,1,0,1,0,0,1,1,
1,1,1,0,0,1,0,0,0,1,
1,0,0,0,1,0,0,1,0,1,
1,1,1,1,1,1,1,1,1,1};

不用那么多个大括号。