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第九题第一个,拜托了,谢谢!
展开全部
y=[x/(x+1)]^x
lny=xln(x/(x+1))=xlnx-xln(x+1)
y'/y=lnx+1-ln(x+1)-x/(x+1)
y'=y[lnx/(x+1)+1/(x+1)]
y'=[lnx/(x+1)+1/(x+1)]*[x/(x+1)]^x
lny=xln(x/(x+1))=xlnx-xln(x+1)
y'/y=lnx+1-ln(x+1)-x/(x+1)
y'=y[lnx/(x+1)+1/(x+1)]
y'=[lnx/(x+1)+1/(x+1)]*[x/(x+1)]^x
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