Question

C++编程含有10个元素的数组,求其中正数,负数,和零的个数

C++编程含有10个元素的数组,求其中正数,负数,和零的个数

Answer 1

#include<iostream>
using namespace std;
int main()
{
int a=0,b=0,c=0,d[10],i;
for(i=0;i<=9;i++)
{
cin>>d[i];
if(d[i]>0)a++;
if(d[i]<0)b++;
else c++;
}
cout<<a<<endl;//正数的个数
cout<<b<<endl;//负数的个数
cout<<c<<endl;//零的个数
return 0;
}

Answer 2

#include<iostream>
using
namespace
std;
int
main()
{
int
a=0,b=0,c=0,d[10],i;
for(i=0;i<=9;i++)
{
cin>>d[i];
if(d[i]>0)a++;
if(d[i]<0)b++;
else
c++;
}
cout<<a<<endl;//正数的个数
cout<<b<<endl;//负数的个数
cout<<c<<endl;//零的个数
return
0;
}

Answer 3

#include<stdio.h>
int a[11],cnt[3];
int idx(int a){return a==0?0:a>0?1:2;}
void main()
{
int i;
for(i=0;i<10;++i)scanf("%d",&a[i]);
for(i=0;i<10;++i)++cnt[idx(a[i])];
printf("The Number that larger than 0 : %d\n",cnt[1]);
printf("The Number that euqal to 0 : %d\n",cnt[0]);
printf("The Number that smaller than 0 : %d\n",cnt[2]);
}

Answer 4

……
int zhengshu=0,fushu=0,ling=0;
int i;
s[10]
……
for(i=0;i<10;i++)
if(s[i]>0 zhengshu++;
else if(s[i]<0 fushu++;
else ling++;
……