
1/3+1/9+5/27 ,2/3+(1/2-1/3),1/8+3/5-3/40。 列递等式?
2个回答
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递等式计算
1/3+1/9+5/27
=9/27+3/27+6/27
=18/27
=2/3
2/3+(1/2-1/3)
=2/3-1/3+1/2
=1/3+1/2
=5/6
1/8+3/5-3/40
=5/40+24/40-3/40
=26/40
=13/20
1/3+1/9+5/27
=9/27+3/27+6/27
=18/27
=2/3
2/3+(1/2-1/3)
=2/3-1/3+1/2
=1/3+1/2
=5/6
1/8+3/5-3/40
=5/40+24/40-3/40
=26/40
=13/20
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