Question

已知a加b等于六a b已知a加b等于六，ab等于五，求倍根号a分之b加a倍根号b分之一的值。

Answer 1

设根号a=A,根号b＝B 则A^2+B^2=6,A^2B^2=4,AB=2 所有为：（A-B)/(A+B) (A-B)^2=A^2-2AB+B^2=6-4=2 (A+B)^2=A^2+2AB+B^2=6+4=10 (A-B)^2/(A+B)^2=2/10=1/5 开方得： (A-B

Answer 2

a b = -3，ab = 2(a b)= 9 a b 2ab = 9 a b 2 * 2 = 9 a b = 5(a b)/(ab)= 5/2 a/b b/a = 5/2 a/b 2 b/a = 5/2 2 { √( a/b)√(b/a)} = 9/2√(a/b)√(b/a)= 3/√2(√( a/b)√( b)=-3/√2无效

Answer 3

设根号a=A,根号b＝B
则A^2+B^2=6,A^2B^2=4,AB=2
所有为：（A-B)/(A+B)
(A-B)^2=A^2-2AB+B^2=6-4=2
(A+B)^2=A^2+2AB+B^2=6+4=10
(A-B)^2/(A+B)^2=2/10=1/5
开方得：
(A-B)/(A+B)=根号5/5

Answer 4

设根号a=A,根号b＝B 则A^2+B^2=6,A^2B^2=4,AB=2 所有为：（A-B)/(A+B)(A-B)^2=A^2-2AB+B^2=6-4=2 (A+B)^2=A^2+2AB+B^2=6+4=10 (A-B)^2/(A+B)^2=2/10=1/5 开方得请点右下角“采纳答案”,支持一下.