Question

x²=(4-x)²+2

过程不要有^号

Answer 1

x²=(4-x)²+2
x²-(4-x)²=2
(x+4-x)(x-4+x)=2
4(2x-4)=2
2x-4=1/2
2x=9/2
x=9/4

Answer 2

x²=(4-x)²+2 先展开括号，然后移项合并同类项，最后将系数化为1，具体步骤如下
x²=(4-x)²+2
x² = 4²-8x+x²+2
x²=16-8x+x²+2
x²=18-8x+x²
x²-x²+8x = 18
8x = 18
x=18 ÷ 8
x=2.25