Question

如果△十△十O=90,△一O一O=15,△=(),O=()？

Answer 1

变形有:2△+O=90,△-2O=15,△=15+2O
即:2(15+2O)+O=90
30+4O+O=90
5O=60
O=12，则△=15+2X12=39

Answer 2

△＋△＋〇＝90
〇＝90一△一△
△一〇一〇＝15
△一（90一△一△）一（90一△一△）＝15
△一90＋△＋△一90＋△＋△＝15
5△＝15＋90＋90
△＝195÷5
△＝39，〇＝12