3*5*17*(2^8+1)简便方法计算,40又2/3*39又1/3
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3*5*17*(2^8+1)
=3*5*17*(2^8+1)(2^8-1)*除以(2^8-1)
=3*5*17*(2^8+1)(2^8-1)*除以[(2^4-1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[(2^2-1)(2^2+1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[(2-1)(2+1)(2^2+1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[1*3*5*17]
=(2^8+1)(2^8-1)
=2^16-1
=65535
40又2/3*39又1/3
=(40+2/3)(40-2/3)
=40^2-(2/3)^2
=1600-4/9
=1599又5/9
=3*5*17*(2^8+1)(2^8-1)*除以(2^8-1)
=3*5*17*(2^8+1)(2^8-1)*除以[(2^4-1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[(2^2-1)(2^2+1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[(2-1)(2+1)(2^2+1)(2^4+1)]
=3*5*17*(2^8+1)(2^8-1)*除以[1*3*5*17]
=(2^8+1)(2^8-1)
=2^16-1
=65535
40又2/3*39又1/3
=(40+2/3)(40-2/3)
=40^2-(2/3)^2
=1600-4/9
=1599又5/9
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