Question

C语言编程“要求输出每月对应的天数”

如题.考试用

Answer 1

C语言实现如下：

#include<stdio.h>
void main()
{
	int year,month;
	int day[12]={31,28,31,30,31,30,31,31,30,31,30,31};
	printf("请输入年份与月份：\n");
	scanf("%d%d",&year,&month);
	if (year%4==0&&year%100!=0||year%400==0) day[1]++;
	//判断是否为闰年，是则给原2月天数加一天。
	printf("%d年%d月有%d天\n",year,month,day[month-1]);
}

Answer 2

#include<stdio.h>
const int month[][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}}
int main()
{ int i;
printf("non-leap year :\n");// 不是闰年
for(i=1;i<13;i++)
printf("%d\t%d\n",i,month[0][i]);
printf("leap year :\n");//闰年
for(i=1;i<13;i++)
printf("%d\t%d\n",i,month[1][i]);
}

Answer 3

用数组就行~
int month[12];

month[0] = 31;
month[1] = 28;
month[2] = 31;
month[3] = 30;
....
month[11] = 31;

然后输入数组咯~