Question

android 中 startService(intent) 为什么不执行service的onStartCommand（），我是新手，请帮忙！谢谢

启动service
Intent intent = new Intent("com.Sevices.mqtt.ReceivingMessageService");
intent.putExtra("message", s);
startService(intent);

注册
<service android:name="com.Sevices.mqtt.ReceivingMessageService"/>

service的onStartCommand方法
public int onStartCommand(Intent intent, int flags, int startId) {
// TODO Auto-generated method stub

Log.i("serv1", "onStartCommand");
String s = intent.getStringExtra("message");
if (s != null && s.length() > 0)
{
Log.i("serv1", "message:"+s);
}

return super.onStartCommand(intent, flags, startId);

}

Answer 1

你只是简单的注册了<service android:name="com.Sevices.mqtt.ReceivingMessageService"/>
并没有给这个service起个名字，所以Intent intent = new Intent("com.Sevices.mqtt.ReceivingMessageService");

这样调用是启动不了你的service的，请改为类似如下：
Intent intent = new Intent(MainActivity.this,com.Sevices.mqtt.ReceivingMessageService.class);

或者在manifest中加个别名：
<service android:name="com.Sevices.mqtt.ReceivingMessageService">
<intent-filter>
<action android:name="com.Sevices.mqtt.ReceivingMessageService" />
</intent-filter>
</service>

Answer 2

If someone calls Context.startService() then the system will retrieve the service (creating it and calling its onCreate() method if needed) and then call itsonStartCommand(Intent, int, int) method with the arguments supplied by the client.
请贴出Service的完整代码