Question

要过程，计算题，快，急，

计算①(a²+3)(a²+9)②(1-4x²)(1+4x²)③(x²)²·x²+x³·x·x²④(a+2b-3)(2a-b) ⑤(2x-1)(x+1)⑥(0.3ab²)²⑦.（-4a)·(2a²+4a-3) 10.(2x-3)(3x+2)

Answer 1

(1)原式=x^4+9a^2+3a^2+27=a^4+12a^2+27
(2)原式=1+4x^2-4x^2-16x^4=1-16x^4
(3)原式=x^4·x^2+x^4·x^2=x^6+x^6=2x^6
(4)原式=2a^2-ab+4ab-2b^2-6a+3b=2a^2+3ab-2b^2-6a+3b
(5)原式=2x^2+2x-x-1=2x^2+x-1
(6)原式=0.3^2·a^2·b^4=0.09a^2·b^4
(7)原式=-8a^3-16a^2+12a
(10)原式=6x^2+4x-9x-6=6x^2-5x-6

追问

谢谢你

Answer 2

①(a²+3)(a²+9)
=a^4+(3+9)a+3×9
=a^4+12a+27

②(1-4x²)(1+4x²)
=1-16x^4

③(x²)²·x²+x³·x·x²
=x^6+x^6
=2x^6

④(a+2b-3)(2a-b)
=2a²-ab+4ab-2b²-6a+3b
=2a²-2b²-6a+3b+3ab

⑤(2x-1)(x+1)
=2x²+2x-x-1
=2x²+x-1

⑥(0.3ab²)²
=0.09a²b^4

⑦.（-4a)·(2a²+4a-3)
=-8a³-16a²+12a

10.(2x-3)(3x+2)
=6x²+4x-9x-6
=6x²-5x-6