求教:用matlab解下面的非线性参联立方程 15
方程1:(log((alpha-1)*(c+omega+k*r-a*f(k)))*((alpha-1)*(c+omega+k*r-a*f(k)))^((Y*alpha)/...
方程1:(log((alpha - 1)*(c + omega + k*r - a*f(k)))*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)))*(Y/(Y*alpha - X*(alpha - 1)) + (Y*alpha*(X - Y))/(Y*alpha - X*(alpha - 1))^2) + (Y*alpha*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)) - 1)*(c + omega + k*r - a*f(k)))/(Y*alpha - X*(alpha - 1)))/(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1))) - ((log(c + omega - alpha*(c + omega + k*r - a*f(k)))*(X/(Y*alpha - X*(alpha - 1)) + (X*(X - Y)*(alpha - 1))/(Y*alpha - X*(alpha - 1))^2))/(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1))) - (X*(alpha - 1)*(c + omega + k*r - a*f(k)))/((Y*alpha - X*(alpha - 1))*(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1)) + 1)))*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)))=0
方程2:(X*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)))*(alpha - 1)^2)/((Y*alpha - X*(alpha - 1))*(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1)) + 1)) + (Y*alpha*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)) - 1)*(alpha - 1))/((Y*alpha - X*(alpha - 1))*(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1))))=0
要联立上述两个方程解出alpha和c用其他参数表示的值,应该怎么做??求高手指点!!万分感谢!!!!! 展开
方程2:(X*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)))*(alpha - 1)^2)/((Y*alpha - X*(alpha - 1))*(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1)) + 1)) + (Y*alpha*((alpha - 1)*(c + omega + k*r - a*f(k)))^((Y*alpha)/(Y*alpha - X*(alpha - 1)) - 1)*(alpha - 1))/((Y*alpha - X*(alpha - 1))*(c + omega - alpha*(c + omega + k*r - a*f(k)))^((X*(alpha - 1))/(Y*alpha - X*(alpha - 1))))=0
要联立上述两个方程解出alpha和c用其他参数表示的值,应该怎么做??求高手指点!!万分感谢!!!!! 展开
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