Question

'C语言 定义一个包含年月日的结构体变量，任意输入一天，计算该日是本年的第几天

Answer 1

#include <stdio.h> 
#include<string.h>

struct date
{
	int year, mouth, day;
};

int main()
{
	struct date d;
	int i, k=0, nday=0;
	
	printf("请输入当前年月日： ");
	scanf("%d%d%d", &d.year, &d.mouth, &d.day);

	///先判断是否是闰年,符合条件就是闰年,k置为1
	if(d.year%4==0 && d.year%100 != 0 || d.year%400 == 0)
		k = 1;

	for(i=1; i<d.mouth; i++)
	{
		//如果是2月并且是闰年，加上29天
		if(i == 2 && k == 1)
			nday += 29;
		else if(i == 2)
			nday += 28;
		else if(i==1 || i==3 || i==5 || i==7 || i==8 || i==10 || i==12)
			nday += 31;
		else
			nday += 30;
	}

	nday += d.day;

	printf("今天是今年的第 %d 天\n", nday);

	return 0;
}

Answer 2

#include <stdio.h>
void main()
{
int year,month,day,days=0,i;
printf("请输入年月日:");
scanf("%d%d%d",&year,&month,&day);
if(year<1 || month>12 || month<1 || day>31)
printf("日期输入错误!!!\n");
else
{
if(month>1)
for(i=1;i<month;i++)
if(i==2)
days+=28;
else if(i==4|| i==6||i==9||i==11)
days+=30;
else
days+=31;
days+=day;
}
if((month>2) && ((year%400==0)||(year%4==0 && year%100!=0)))
days+=1;
printf("%d年%d月%d日是%d年%d天!\n",year,month,day,year,days);
}

Answer 3

追答

#include
int main()
{struct dat{int y,m,d;}date;
int i,n;
scanf("%d%d%d",&date.y,&date.m,&date.d);
n=date.d;
for(i=1;i0||date.y%400==0)n+=29;
else n+=28;
}
printf("%d-%d-%d is No.%d day of %d\n",date.y,date.m,date.d,n,date.y);
return 0;
}

Answer 4

#include <stdio.h>
#include<string.h>
struct date
{
int year,mouth,day;
};
int main()
{
struct date d;
int i,k=0,nday=0;
scanf("%d%d%d", &d.year,&d.mouth,&d.day);
if(d.year%4==0&& d.year%100!=0|| d.year%400==0)
k=1;
for(i=1;i<d.mouth;i++)
{
if(i==2&&k==1)
nday+=29;
else if(i==2)
nday+=28;
else if(i==1||i==3 ||i==5||i==7||i==8 ||i==10||i==12)
nday+=31;
else
nday+=30;
}
nday+=d.day;
printf("%d",nday);
return 0;
}