Question

C# list<string> 怎么提取需要的内容并存入其他数组

例如list<string>s里有从文本里读取的
“X100.013 Y111.084 Z1.07050”
“X100.049 Y110.931 Z1.07569”
“X100.191 Y110.652 Z1.08603”
“X100.412 Y110.431 Z1.09638”
“X100.691 Y110.289 Z1.10673”
“X100.844 Y110.253 Z1.11192”
“X101.008 Y110.240 Z1.11737”
怎么把其中的X\Y坐标存入二维数组呢？

Answer 1

用正则表达式来实现

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;

namespace ConsoleApplication2
{
    class Program
    {
        //定义一个结构存放X,Y坐标
        struct MyPoint
        {
            public float x;
            public float y;
            public override string ToString()
            {
                return string.Format("x={0}, y={1}", x, y);
            }
        }

        static void Main(string[] args)
        {
            //存放提取出的坐标点
            List<MyPoint> pointList = new List<MyPoint>();
            
            List<string> list = new List<string>()            {
                    "X100.013 Y111.084 Z1.07050",
                    "X100.049 Y110.931 Z1.07569",
                    "X100.191 Y110.652 Z1.08603",
                    "X100.412 Y110.431 Z1.09638",
                    "X100.691 Y110.289 Z1.10673",
                    "X100.844 Y110.253 Z1.11192",
                    "X101.008 Y110.240 Z1.11737"
            };
            
            //匹配模式串
            string pattern = @"X(?<x>\d+.\d+) Y(?<y>\d+.\d+) Z\d+.\d+";
            foreach (string s in list)
            {
                Match match = Regex.Match(s, pattern);
                if (match.Success)
                {
                    //从配合结果中取出x,y，并转换成浮点数
                    float xV = float.Parse(match.Result("${x}"));
                    float yV = float.Parse(match.Result("${y}"));
                    //存放到集合中
                    pointList.Add(new MyPoint() { x = xV, y = yV });
                }
            }
            
            // 结果数组
            MyPoint[] points = pointList.ToArray();

            // 显示提前结果
            for (int i = 0; i < points.Length; i++)
            {
                Console.WriteLine(points[i].ToString());
            }
        }
    }
}

Answer 2

我也来凑凑热闹，试著用Linq，感觉不错哦

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace LinqTest1
{
    struct DoublePoint
    {
        private double x;
        private double y;
        public DoublePoint(double[] a)
        {
            this.x = a[0];
            this.y = a[1];
        }
        public double X
        {
            get { return this.x; }
            set { this.x = value; }
        }
        public double Y
        {
            get { return this.y; }
            set { this.y = value; }
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            List<string> list = new List<string>() { "X100.013 Y111.084 Z1.07050",
                                                                                "X100.049 Y110.931 Z1.07569",
                                                                                "X100.191 Y110.652 Z1.08603",
                                                                                "X100.412 Y110.431 Z1.09638",
                                                                                "X100.691 Y110.289 Z1.10673",
                                                                                "X100.844 Y110.253 Z1.11192",
                                                                                "X101.008 Y110.240 Z1.11737"};
            var a = from item in list select new DoublePoint(Array.ConvertAll(item.Replace("X", "").Replace("Y", "").Substring(0, item.IndexOf(" Z") - 2).Split(' '), Double.Parse));
            DoublePoint[] value = a.ToArray();
        }
    }
}

Answer 3

你这些里的这些数字那么整齐还能不好存么，用一个for循环或者foeach循环，把这些数据全部遍历一遍，因为你这些数字过于整齐了，所以你完全可以拿出一项之后 s[i].substring（1,7）,这样就拿出x了，同样s[i].substring（10,7）就拿出y了，因为你拿出来是string，记得再Convet.Double一下，就行了，拿出来的坐标你可以去定义一个二维数组都给放进去就行了。

Answer 4

List<double[]> list=new List<double[]>();
foreach(string str in s)
{
string[] arr=str.Split(new char[]{' '},StringSplitOption.RemoveEmptyEntries);
if(arr.Length>=2)
{
doube x=Convert.ToDouble(arr[0].Trim('X'));
doube y=Convert.ToDouble(arr[1].Trim('Y'));
list.Add(new double[]{x,y});
}
}

//list就是你要的结果了

Answer 5

float[] getzXYZ(string t)
        {
            if (t.IndexOf("X")<0 ||t.IndexOf("Y")<0||t.IndexOf("Z")<0)
            {
                return null;

            }

            string sx = t.Substring(t.IndexOf("X"), t.IndexOf("Y") - t.IndexOf("X")).Substring(1);
            string sy = t.Substring(t.IndexOf("Y"), t.IndexOf("Z") - t.IndexOf("Y")).Substring(1);
            string sz = t.Substring(t.IndexOf("Z")).Substring(1);

            float x = float.Parse(sx);
            float y = float.Parse(sy);
            float z = float.Parse(sz);
            float[] rtn=new float[3];
            rtn[0]=x;
            rtn[1]=y;
            rtn[2]=z;
            return rtn;
        }
        //自己迭代