因式分解1.m²-2mn+n²-4m+4n-5 2.x^4+x²y²+y^4 3.(x²+x-4)(x²+x+3)+10
2个回答
展开全部
m²-2mn+n²-4m+4n-5
=(m²-2mn+n²)-4(m-n)-5
=(m-n)²-4(m-n)-5
=[(m-n)+1][(m-n)-5]
=(m-n+1)(m-n-5)
x^4+x²y²+y^4
=(x²+y²)²-x²y²
=(x²+y²+xy)(x²+y²-xy)
(x²+x-4)(x²+x+3)+10
=(x²+x)²-(x²+x)-12+10
=(x²+x)²-(x²+x)-2
=[(x²+x)+1][(x²+x)-2]
=(x²+x+1)(x²+x-2)
展开全部
1、m²-2mn+n²-4m+4n-5
=(m-n)^2-4(m-n)-5
=(m-n-5)(m-n+1)
2、x^4+x²y²+y^4
=(x^2+y^2)^2-x²y²
=(x^2+y^2-xy)(x^2+y^2+xy)
3、(x²+x-4)(x²+x+3)+10
=(x²+x)^2-(x²+x)-12+10
=(x²+x)^2-(x²+x)-2
=(x²+x-2)(x²+x+1)
=(x+2)(x-1)(x²+x+1)
4、x²-xy-6y²-x+8y-2
=x²-x(y+1)-(6y²-8y+2)
=x²-x(y+1)-(3y-1)(2y-2)
=(x-3y+1)(x+2y-2)
=(m-n)^2-4(m-n)-5
=(m-n-5)(m-n+1)
2、x^4+x²y²+y^4
=(x^2+y^2)^2-x²y²
=(x^2+y^2-xy)(x^2+y^2+xy)
3、(x²+x-4)(x²+x+3)+10
=(x²+x)^2-(x²+x)-12+10
=(x²+x)^2-(x²+x)-2
=(x²+x-2)(x²+x+1)
=(x+2)(x-1)(x²+x+1)
4、x²-xy-6y²-x+8y-2
=x²-x(y+1)-(6y²-8y+2)
=x²-x(y+1)-(3y-1)(2y-2)
=(x-3y+1)(x+2y-2)
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询