Question

HttpWebRequest发送post请求时有多个参数如何处理

Answer 1

tring strURL = "http://localhost/Play/CH1/Service1.asmx/doSearch";
System.Net.HttpWebRequest request;
request = (System.Net.HttpWebRequest)WebRequest.Create(strURL);
//Post请求方式
request.Method="POST";
// 内容类型
request.ContentType="application/x-www-form-urlencoded";
// 参数经过URL编码

//这是原始代码：
string paraUrlCoded = System.Web.HttpUtility.UrlEncode("keyword");
paraUrlCoded += "=" + System.Web.HttpUtility.UrlEncode(this.textBox1.Text);