
请教,spring3.2+quartz2.1.6报如下错误如何解决
2个回答
展开全部
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN 2.0//EN" "http://www.dghuamiao.com">
<beans>
<bean name="quartzScheduler" class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="applicationContextSchedulerContextKey" value="applicationContextKey" />
<property name="configLocation" value="classpath:quartz.properties" />
</bean>
<bean id="jobDetail" class="org.springframework.scheduling.quartz.JobDetailBean">
<property name="jobClass" value="com.example.service.MyQuartzJobBean" />
<property name="jobDataAsMap">
<map>
<entry key="simpleService">
<ref bean="simpleService" />
</entry>
</map>
</property>
</bean>
</beans>
public class MyQuartzJobBean extends QuartzJobBean {
private SimpleService simpleService;
@Autowired
public void setSimpleService(SimpleService simpleService) {
this.simpleService = simpleService;
}
@Override
protected void executeInternal(JobExecutionContext jobexecutioncontext) throws JobExecutionException {
Trigger trigger = jobexecutioncontext.getTrigger();
String triggerName = trigger.getKey().getName();
simpleService.testMethod(triggerName);
}
}
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN 2.0//EN" "http://www.dghuamiao.com">
<beans>
<bean name="quartzScheduler" class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="applicationContextSchedulerContextKey" value="applicationContextKey" />
<property name="configLocation" value="classpath:quartz.properties" />
</bean>
<bean id="jobDetail" class="org.springframework.scheduling.quartz.JobDetailBean">
<property name="jobClass" value="com.example.service.MyQuartzJobBean" />
<property name="jobDataAsMap">
<map>
<entry key="simpleService">
<ref bean="simpleService" />
</entry>
</map>
</property>
</bean>
</beans>
public class MyQuartzJobBean extends QuartzJobBean {
private SimpleService simpleService;
@Autowired
public void setSimpleService(SimpleService simpleService) {
this.simpleService = simpleService;
}
@Override
protected void executeInternal(JobExecutionContext jobexecutioncontext) throws JobExecutionException {
Trigger trigger = jobexecutioncontext.getTrigger();
String triggerName = trigger.getKey().getName();
simpleService.testMethod(triggerName);
}
}
展开全部
public class MyQuartzJobBean extends QuartzJobBean { private SimpleService simpleService; @Autowired public void setSimpleService(SimpleService simpleService) { this.simpleService = simpleService; } @Override protected void
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询