Question

关于x的方程x^2-2mx=负m的方 2x的两个实数根x1x2满足x1绝对值=x二求实数m的值

Answer 1

x²-2mx=-m²+2x;
x²-(2m+2)x+m²=0;
x1+x2=2m+2;
x1x2=m²;
∵|x1|=x2;
∴x1=±x2;
(1)x1=x2;x1=x2=m+1;(m+1)²=m²;
(2m+1)×1=0;
m=-1/2;
(2)x1=-x2;2m+2=0;m=-1;