Question

<input type="file">如何在后台取值？

如何在.ashx中获得上传的值？
HTML:
<form id="form1" enctype="multipart/form-data" action="BrandManager.ashx">
<input id="logo" type="file" name="update" />
ASHX:
if (context.Request.Files.Count == 0)
{
return;
}COUNT 总是为零

Answer 1

HttpFileCollection Files = HttpContext.Current.Request.Files;

Response.Write(Files.Count);