展开全部
dy/dx =y/x + tan(y/x)
let
u=y/x
du/dx = (x.dy/dx - y) /x^2
= (1/x) dy/dx - y/x^2
dy/dx = x.du/dx + u
---------
dy/dx =y/x + tan(y/x)
x.du/dx + u = u + tanu
x.du/dx = tanu
∫du/tanu = ∫dx/x
ln|sinu| = ln|x| + C'
sinu = Cx
sin(y/x)=Cx
ans : C
let
u=y/x
du/dx = (x.dy/dx - y) /x^2
= (1/x) dy/dx - y/x^2
dy/dx = x.du/dx + u
---------
dy/dx =y/x + tan(y/x)
x.du/dx + u = u + tanu
x.du/dx = tanu
∫du/tanu = ∫dx/x
ln|sinu| = ln|x| + C'
sinu = Cx
sin(y/x)=Cx
ans : C
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询