Question

初二因式分解

Answer 1

已知：a=10000, b=9999
解：原式=（a^2+b^2-2ab)-6(a-b)+q=(a-b）^2
=(10000-9999)^2-6(10000-9999)+q
=1^2-6*1+q=-5+q

Answer 2

=a²(x-y)-b²(x-y)
=(x-y)(a²+n²
=(4m²-b²-(3b)²
=(a+3b)(a-3b)

解(2) -16m²+(m-n)²
=(m-n)²-16m²
=(m-n)²-(4m)²)(4m²-n²-4(2x-y)²
=[(m-n)+4m][(m-n)-4m]
=(5m-n)(-3m-n)
=-(5m-n)(3m+n)

解(3) (x-2y)²)
=(x-y)(a+b)(a-b)

解(5) 16m^4-n^4 ^表示乘方
=(4m²)-(n²)²
=(x-2y)²-[2(2x-y)]²
=[(x-2y)+2(2x-y)][(x-2y)-2(2x-y)]
=(x-2y+4x-2y)(x-2y-4x+2y)
=-3x(5x-4y)

解(4) a²解(1) a²-9b²

Answer 3