如图!谢谢!
展开全部
Z=-j10+(1/10+1/j10)
=-j10+0.1-j0.1
=0.1-j10.1
i=Us/Z
=10(0.1+j10.1)/(0.1²+10.1²)=0.09802(0.1+j10.1)=0.009802+j0.990002
=0.9901(0.00990+j0.99995)
Uc=i(-j10)=(0.009802+j0.990002)(-j10)=9.90002-j0.09802
UR=UL=Us-Uc=10-9.90002+j0.09802=0.09998+j0.09802=0.14(0.7141+j0.7001)
i1=UR/10=0.009998+j0.009802=0.014(0.7141+j0.7001)
i2=i-i1=9.90002-j0.09802-0.009998-j0.009802
=9.890022-j0.107822
有功功率是R消耗的功率:
=i1²R=(0.014/√2)²10=0.00098W
=uR²/R=(0.14/√2)²/10
总功率=Usi=10/√2×0.9901/√2=4.9505W
=-j10+0.1-j0.1
=0.1-j10.1
i=Us/Z
=10(0.1+j10.1)/(0.1²+10.1²)=0.09802(0.1+j10.1)=0.009802+j0.990002
=0.9901(0.00990+j0.99995)
Uc=i(-j10)=(0.009802+j0.990002)(-j10)=9.90002-j0.09802
UR=UL=Us-Uc=10-9.90002+j0.09802=0.09998+j0.09802=0.14(0.7141+j0.7001)
i1=UR/10=0.009998+j0.009802=0.014(0.7141+j0.7001)
i2=i-i1=9.90002-j0.09802-0.009998-j0.009802
=9.890022-j0.107822
有功功率是R消耗的功率:
=i1²R=(0.014/√2)²10=0.00098W
=uR²/R=(0.14/√2)²/10
总功率=Usi=10/√2×0.9901/√2=4.9505W
更多追问追答
追问
电阻和电感不是并联吗?并联公式不应该求导相加再求导吗
追答
对,写错了,少一个倒数:
Z=-j10+1/(1/10+1/j10)
=-j10+1/(0.1-j0.1)
=-j10+10(1+j)/(1+1)
=-j10+5(1+j)
=5-j5
下面做法相同。
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询