[100x+(8-x)]-[(8-x)ⅹ100+x]
1个回答
2020-02-07
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[100x+(8-x)]-[(8-x)ⅹ100+x]
=(100x-x+8)-(800-100x+x)
=(99x+8)-(800-99x)
=99x+8-800+99x
=198x-792
=(100x-x+8)-(800-100x+x)
=(99x+8)-(800-99x)
=99x+8-800+99x
=198x-792
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