Question

(2+1)(2的平方+1)(2的4次方+1)(2的八次方+1)+……（2的128次方+1）+1

给过程
为什么啊

Answer 1

(2-1)(2+1)(2的平方+1)(2的4次方+1)(2的八次方+1)+……（2的128次方+1）+1

(2^2-1)(2的平方+1)(2的4次方+1)(2的八次方+1)+……（2的128次方+1）+1

依此类推
(2^128-1)(2^128+1)+1
=2^256

Answer 2

(2-1)*(2+1)(2的平方+1)(2的4次方+1)(2的八次方+1)+……（2的128次方+1）+1
=2的256次方-1+1
=2的256次方

Answer 3

(2+1)(2^2+1)(2^4+1)~~~~(2^128+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)~~~~(2^128+1)+1
=(2^2-1)(2^2+1)(2^4+1)~~~~(2^128+1)+1
=(2^4-1)(2^4+1)~~~~(2^128+1)+1
~~~~~~~~
=(2^256-1)+1
=2^256