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f'x = -1/(x-y)^2 (x-y)'x = -1/(x-y)^2 (chain rule)
f'y = -1/(x-y)^2 (x-y)'y = 1/(x-y)^2 (chain rule)
f'y = -1/(x-y)^2 (x-y)'y = 1/(x-y)^2 (chain rule)
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展开全部
f(x,y) =1/(x-y)
∂/∂x f(x,y) = -1/(x-y)^2
∂/∂y f(x,y) = 1/(x-y)^2
∂/∂x f(x,y) = -1/(x-y)^2
∂/∂y f(x,y) = 1/(x-y)^2
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