Question

x^3-3x+2如何因式分解？我记得有一种很想除嘚方法但是不知道确切嘚名字

Answer 1

x³-3x+2
=x³-x-2x+2
=x(x²-1)-2(x-1)
=x(x-1)(x+1)-2(x-1)
=(x-1)(x²+x-2)
=(x-1)(x-1)(x+2)
=(x-1)^2(x+2)
用的是分组分解法。

Answer 2

x^3-3x+2
=x^3-1-3x+3
=(x^3-1)-3(x-1)
=(x－1﹚﹙x²＋x＋1﹚－3﹙x－1﹚
=﹙x－1﹚﹙x²＋x-2﹚
=﹙x－1﹚﹙x－1﹚﹙x＋2﹚
=﹙x－1﹚²﹙x＋2﹚

Answer 3

x^3-3x+2
=x^3-x -2x +2
=x(x^2-1) -2(x-1)
=x(x+1)(x-1)-2(x-1)
=(x-1)(x^2+x-2)
=(x-1)(x+2)(x-1)

Answer 4

=X^3-X-2(x-1)
=(X^2+X)(X-1)-2(X-1)

追答

=(X^2+X-2)(X-1)

=(X+2)(X-1)^2

Answer 5

特殊执法(x-1)(x+2)(x-1)

Answer 6

用十字相乘法

Answer 7

（x-1）^2（x+2）