Question

矩阵键盘问题高分望解决

程序如下：
#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
#define p0 P0
#define p3 P3
sbit duanx=P2^6;
sbit weix=P2^7;
uchar key,keing,view;
uchar show[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0xfd};

void delay(uint t)
{
while(--t);
}

void keyscan(void)
{
p3=0xf0;
delay(20);
keing=p3;
keing=keing&0xf0;
if(keing==0x70) key=0;
else if(keing==0xb0) key=1;
else if(keing==0xd0) key=2;
else if(keing==0xe0) key=3;
else key=16;
p3=0x0f;
delay(20);
keing=p3;
keing=keing&0x0f;
if(keing==0x07) key=key+12;
else if(keing==0x0b) key=key+8;
else if(keing==0x0d) key=key+4;
else if(keing==0x0e) key=key+0;
else key=16;
view=show[key];
}

void display(uchar view)
{
p0=view;
duanx=1;
duanx=0;
p0=0xfe;
weix=1;
weix=0;
delay(2000);
}

main()
{
while(1)
{
p0=0xff;
p3=0xff;
display(show[16]);
delay(200);
p3=0x0f;
if(p3!=0x0f)
{
keyscan();
display(view);
}
}
}
原理图如下：

程序一开始一直是显示数字6，我的想法是通过矩阵键盘输入，并显示在一位数码管上。。。大家帮忙看看，指出真正的问题所在，问题解决了追加积分。

Answer 1

#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char

sbit duanx = P2^6;
sbit weix = P2^7;
uchar key, k_tmp, view;

uchar show[] = {
0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x40};

void keyscan(void)
{
key = 16;
P3 = 0xf0; k_tmp = P3 & 0xf0;
if (k_tmp == 0x70) key = 0;
else if(k_tmp == 0xb0) key = 1;
else if(k_tmp == 0xd0) key = 2;
else if(k_tmp == 0xe0) key = 3;
P3 = 0x0f; k_tmp = P3 & 0x0f;
if (k_tmp == 0x07) key = key + 12;
else if(k_tmp == 0x0b) key = key + 8;
else if(k_tmp == 0x0d) key = key + 4;
else if(k_tmp == 0x0e) key = key + 0;

view = show[key];

}

void display(uchar view)
{
P0 = view; duanx = 1; duanx = 0;
P0 = 0xfe; weix = 1; weix = 0;
}

main()
{
while(1) {
keyscan();
display(view);
}
}