化简求值:(1)2cos10°?sin20°cos20°;(2)已知cos(α-β2)=-19,sin(α2-β)=23,且π2<α<
化简求值:(1)2cos10°?sin20°cos20°;(2)已知cos(α-β2)=-19,sin(α2-β)=23,且π2<α<π,0<β<π2,求cosα+β2的...
化简求值:(1)2cos10°?sin20°cos20°;(2)已知cos(α-β2)=-19,sin(α2-β)=23,且π2<α<π,0<β<π2,求cosα+β2的值.
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(1)∵2cos10°=2sin80°
=2sin(60°+20°)
=2(
cos20°+
sin20°)
=
cos20°+sin20°,
∴
=
=
.
(2)cos(α-
)=-
,sin(
-β)=
,且
<α<π,0<β<
,
∴α-
∈(
,π),∴sin(α-
)=
=2sin(60°+20°)
=2(
| ||
2 |
1 |
2 |
=
3 |
∴
2cos10°?sin20° |
cos20° |
| ||
cos20° |
3 |
(2)cos(α-
β |
2 |
1 |
9 |
α |
2 |
2 |
3 |
π |
2 |
π |
2 |
∴α-
β |
2 |
π |
4 |
β |
2 |
1?(? |