Question

c语言编程题，题目如图，麻烦会的亲写一下过程，谢谢！

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

int main(void)
{
    const char operators[4] = {'+','-','*','/'};
    double number1;
    double number2;
    double result = 0;//计算结果变量
    char rand_operator;
    srand((unsigned)time(NULL));//设置时间种子

    rand_operator = operators[rand()%4];//随机抽取运算符号
    number1 = (double)(rand())/100;//产生小数为两位的随机小数
    number2 = (double)(rand())/100;

    switch(rand_operator)
    {
        case '+':
            result = number1 + number2;
            break;
        case '-':
            result = number1 - number2;
            break;
        case '*':
            result = number1 * number2;
            break;
        case '/':
            result = number1 / number2;
            break;
        default:
            printf("error!\n");//如果出错，那么退出程序
            exit(-1);
    }

    printf("%.2f %c %.2f = %.2f\n",number1,rand_operator,number2,result);//打印结果

    return 0;
}

望采纳！

Answer 2

/*
编写一个产生随机简单表达式的程序（如3.4+196.7），形式如下：number1 operator number2
随机产生 number 和 operator
number： 一位小数
operator：+ - * /
计算结果以两位小数显示
*/

/*
double cout =0.0;
//number1 ，menber2随机产生
double number1 ,menber2;
//随机产生操作符
char oper[5]="+-*/";
int a =rand()%4;
char ch = oper [a];

switch ( ch)
{
case '+':cout =number1 +menber2;
case '-':cout =number1 -menber2;
case '*':cout =number1 *menber2;
case '/':cout =number1 +menber2;
}

*/

Answer 3

#include <stdio.h>
#include <math.h>

void main()
{
   double number1,number2;
   double result; 
   char operator;
   number1=rand()*100;
   number2=rand()*200;
   switch(rand()*4)
   {
    case 0: operator='+';result=number1+number2;break;
    case 1: operator='-';result=number1-number2;break;
    case 2: operator='*';result=number1*number2;break;
    default: operator='/';result=number1/number2;break;     
   }
   printf("%5.2f%c%5.2f=%10.2f\n",number1,operator,number2,result);        
}    

怎么又是你？