求解这几道题 高数简单求极限
1个回答
2017-09-26
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原式=lim(x->0) e^ln[x^(-100)*e^(-1/x^2)]
=e^lim(x->0) [-100lnx-1/x^2]
=(1/e)^lim(x->0) [(100x^2*lnx+1)/x^2]
=(1/e)^lim(x->0) [(200x*lnx+100x)/2x]
=(1/e)^lim(x->0) (100lnx+50)
=(1/e)^(-∞)
=+∞
=e^lim(x->0) [-100lnx-1/x^2]
=(1/e)^lim(x->0) [(100x^2*lnx+1)/x^2]
=(1/e)^lim(x->0) [(200x*lnx+100x)/2x]
=(1/e)^lim(x->0) (100lnx+50)
=(1/e)^(-∞)
=+∞
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