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原式 = lim<n→∞>[(n+1-2)/(n+1)]^n = lim<n→∞>[1-2/(n+1)]^n
= lim<n→∞>{[1-2/(n+1)]^[-(n+1)/2]}^[-2n/(n+1)]
= e^[lim<n→∞>-2n/(n+1)] = e^[lim<n→∞>-2/(1+1/n)] = e^(-2) = 1/e^2
= lim<n→∞>{[1-2/(n+1)]^[-(n+1)/2]}^[-2n/(n+1)]
= e^[lim<n→∞>-2n/(n+1)] = e^[lim<n→∞>-2/(1+1/n)] = e^(-2) = 1/e^2
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