Question

求y=x²和y=x围成的面积

Answer 1

请

Answer 2

y=x^2
y=x
x^2=x
x=0 or 1
A
= ∫ (0->1) ( x-x^2) dx
=[ (1/2)x^2 -(1/3)x^3 ]|(0->1)
=1/6