已知F(x)=(x+1)(x-1)(x-2)(x-3)(x-4)求f(1)的导数
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f(x)=(x+1)(x-1)(x-2)(x-3)(x-4)
f'(x)=(x+1)'(x-1)(x-2)(x-3)(x-4)+(x+1)(x-1)'(x-2)(x-3)(x-4)+(x+1)(x-1)(x-2)'(x-3)(x-4)+(x+1)(x-1)(x-2)(x-3)'(x-4)+(x+1)(x-1)(x-2)(x-3)(x-4)'
=(x-1)(x-2)(x-3)(x-4)+(x+1)(x-2)(x-3)(x-4)+(x+1)(x-1)(x-3)(x-4)+(x+1)(x-1)(x-2)(x-4)+(x+1)(x-1)(x-2)(x-3)
f(1)=0+(1+1)(1-2)(1-3)(1-4)+0+0+0=2*(-1)*(-2)*(-3)=-12
望采纳，如有不妥请回复。
f'(x)=(x+1)'(x-1)(x-2)(x-3)(x-4)+(x+1)(x-1)'(x-2)(x-3)(x-4)+(x+1)(x-1)(x-2)'(x-3)(x-4)+(x+1)(x-1)(x-2)(x-3)'(x-4)+(x+1)(x-1)(x-2)(x-3)(x-4)'
=(x-1)(x-2)(x-3)(x-4)+(x+1)(x-2)(x-3)(x-4)+(x+1)(x-1)(x-3)(x-4)+(x+1)(x-1)(x-2)(x-4)+(x+1)(x-1)(x-2)(x-3)
f(1)=0+(1+1)(1-2)(1-3)(1-4)+0+0+0=2*(-1)*(-2)*(-3)=-12
望采纳，如有不妥请回复。
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