若f(x)=1╱3x³+3xf'(0),则f'(0)＝,f(0)＝
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f(x)=(1/3)x^3+3xf'(0)
x=0
f(0)=(1/3)0^3+3(0)f'(0) =0
f(x)=(1/3)x^3+3xf'(0)
f'(0)
=lim(h->0)[ f(h) -f(0)] /h
=lim(h->0)[ (1/3)h^3+3hf'(0)] /h
=lim(h->0)[ (1/3)h^2+3f'(0)]
= 0+ 3f'(0)
=> f'(0) = 0
x=0
f(0)=(1/3)0^3+3(0)f'(0) =0
f(x)=(1/3)x^3+3xf'(0)
f'(0)
=lim(h->0)[ f(h) -f(0)] /h
=lim(h->0)[ (1/3)h^3+3hf'(0)] /h
=lim(h->0)[ (1/3)h^2+3f'(0)]
= 0+ 3f'(0)
=> f'(0) = 0
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