Question

关于批处理替换字符串

有连个文件a.java,b.txt.
a.java的内容是
static final int tempvalue1 = 1;
static final int tempvalue2 = 2;
static final int tempvalue3 = 3;
b.txt的内容是
static final int tempvalue2 = 22;
static final int tempvalue3 = 33;
static final int tempvalue4 = 4;
如果b.txt的每一行变量在a.java中存在则替换其值，如果不存在则添加到a.java中，例如b.txt中的static final int tempvalue2 、static final int tempvalue3在a.java中存在则修改a.java中的static final int tempvalue2 、static final int tempvalue3的值，有如b.txt中static final int tempvalue4 = 4 在a.java中不存在则添加这行到a.java末尾。
结果生成的新文件a.java内容为：
static final int tempvalue1 = 1;
static final int tempvalue2 = 22;
static final int tempvalue3 = 33;
static final int tempvalue4 = 4;
用批处理实现！

Answer 1

@echo off& for %%9 in ("b.txt" "a.java")do for /f "usebackq tokens=1-2 delims==" %%1 in ("%%~F9")do if not defined %%1 set "%%1=wind"&& echo %%1=%%2 >>smile
sort < smile >"a.java"& del=smile

Answer 2

@echo off&if exist 2.txt error>2.txt 2>nul
for /f "delims=" %%a in (b.txt)do (echo %%a)>>new.txt
move "new.txt" "a.java"