Question

一道数学题目！！高手来吧～

一道计算题，需要过程！
[-(1)^2] * [(-3)^2] - [(-1/2)^2003] * [(-2)^2002] / [(2/9)]

请大家尽量看懂，我可能会补充，我想应该看得懂吧。“^”后面就是XX的次方
十分感谢你

Answer 1

[-(1)^2] * [(-3)^2]=-9
[(-1/2)^2003] * [(-2)^2002]=-1/2
原式= -9 - (-1/2)*9/2 = -27/4

西域玄铁对[(-1/2)^2003] * [(-2)^2002] 的解释是对的，可惜后面算错了。nkhui对[-(1)^2] * [(-3)^2]的计算是错误的，其他部分到对

Answer 2

[(-1/2)^2003] * [(-2)^2002]
=[(-1/2)*(1/2)^2002]*2^2002
=(-1/2)*[(1/2)*2]^2002
=-1/2

其他的应该好算的，带进去就可以算出来了

原式=-1*9-（-1/2）*2/9
=-1/9+1/9
=0

Answer 3

[-(1)^2] * [(-3)^2] - [(-1/2)^2003] * [(-2)^2002] / [(2/9)]
=(-1)*9-[-2^2002/(2^2003)]*(9/2)
=-9+(1/2)*(9/2)
=-9+9/4
=-27/4

Answer 4

=-1*9+1/2*9/2
=-9+9/4
=-27/4

Answer 5

[-(1)^2] * [(-3)^2] - [(-1/2)^2003] * [(-2)^2002] / [(2/9)]
=1*9-(-1/2)*[(-1/2)*(-2)]^2002/(2/9)
=9-(-1/2)/(2/9)
=9+9/4
=45/4