Question

请教php大神，如何提取一个json数据里的某值？

{"code":"0","data":[{"sub":"iat","auth_id":"688093481a516772850fe01f02b1896a","text":{"bg":0,"ed":0,"ls":false,"sn":1,"ws":[{"bg":1,"cw":[{"sc":0,"w":"200"}]},{"bg":1,"cw":[{"sc":0,"w":"-"}]},{"bg":1,"cw":[{"sc":0,"w":"99"}]},{"bg":1,"cw":[{"sc":0,"w":"等于"}]},{"bg":1,"cw":[{"sc":0,"w":"多少"}]}]},"result_id":1},{"sub":"iat","auth_id":"688093481a516772850fe01f02b1896a","text":{"bg":0,"ed":0,"ls":true,"sn":2,"ws":[{"bg":0,"cw":[{"sc":0,"w":""}]}]},"result_id":2},{"sub":"nlp","auth_id":"688093481a516772850fe01f02b1896a","intent":{},"result_id":2},{"sub":"nlp","auth_id":"688093481a516772850fe01f02b1896a","intent":{"answer":{"text":"等于101","type":"T"},"expression":"200-99","match_info":{"type":"gparser_path","value":"----------"},"operation":"ANSWER","rc":0,"service":"calc","sid":"atn0054134e@dx00070ee3fb04a10e01","state":{"fg::weather::default::default":{"state":"default"}},"text":"200-99等于多少","uuid":"atn0054134e@dx00070ee3fb04a10e01"},"result_id":1}],"desc":"success","sid":"ara0013dcae@dx2c850ee3fb04090000"}我想提取最后一组data【3】里的intent下的text值和intent下的answer下的text值请教php源码，谢谢

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Answer 1

这个问题很简单，在php里json格式就是字符串，可以用php内置函数json_decode($json,true)转化成数组，取嫌肆数组的值带消你芹行轿应该知道怎么弄了吧

追问

取code、sid我知道
$object = json_decode($result);
echo $object->sid;
echo $object->code;
但是取data【3】里的intent下的text值和intent下的answer下的text值就真的不知道了，小白。请赐教