Question

关于<input type=radio>的问题???

<form>
<input type="radio" name="type" value="1" checked="checked">网页1<input type="radio" name="type" value="2">网页2
<INPUT type=submit name=submit>
</form>

如何实现点击按扭后跳转到radio所选择的网页,求PHP代码,或用JS实现也可以!!!!!!!!

Answer 1

<script>
var val=1;
function func(){
if( val==1 ){
location.reload("1");//双引号里写第一个页面的地址
}else if( val==2 ){
location.reload("2");//双引号里写第二个页面的地址
}
}
</script>

<form>
<input type="radio" name="type" value="1" checked="checked" onclick="val=1;">网页1
<input type="radio" name="type" value="2" onclick="val=2;">网页2
<input type="button" name="submit" value="提交" onclick="func();">
</form>

Answer 2

<form method="POST" name=form1 action="" onSubmit="return chk();">
<input type="radio" name="type" value="1" checked="checked">网页1<input type="radio" name="type" value="2">网页2
<INPUT type=submit name=submit>
</form>
<script language="javascript">
function chk()
{
for(i=0;i<document.form1.type.length;i++)
{
if(document.form1.type[i].checked==true)
{
document.form1.action=document.form1.type[i].value+".asp";
}
}
}
</script>