Question

C语言编程1+1/+2+1/3+1/4+1/5+···+1/n

我才开始学，今天的作业，跪求高手给个答案。

Answer 1

#include "stdafx.h"
#include <iostream.h>

double Fun( int n)
{
double sum = 0;
for(int i =1; i< n+1 ;i++)
{
sum = sum +( double )1/i;
}
return sum;
}
int main(int argc, char* argv[])
{
cout<<Fun(10);
cin;
return 0;
}

Answer 2

#include<stdio.h>
int main(void)
{
int n;
double sum,i;
sum=0;
printf("Please input N:");
scanf("%d",&n);
for(i=1;i<=n;i++)
sum=sum+1/i;
printf("%lf",sum);
return 0;
}

Answer 3

#include<stdio.h>

int main(void)
{
float a, b, c, sum;

sum = 0;
c = 0;
scanf("%f", &b);
for (a = 1; a <= b; a++)
{
c = 1 / a;
sum += c;
}
printf("1 + 1 / 2 + ..... + 1 / %f, %f", b, sum);

return 0;
}

Answer 4

#include<stdio.h>
void main()
{
float i,s=0,N;
scanf("%f",&N);
for(i=1;i<=N;i++)
s+=1/i;
printf("%f\n",s);
}
这样就可以了.