Question

c# 求出1～1000之间的所有能被7整除的数，并计算和输出每5个的和。

Answer 1

int fivetotal=0;
int Max=1000;
int Min=1;
int Count=Max/7-Min/7;//1-1000能被7整除的个数
int index=1;
while(index<=Count)
{
fivetotal+=index*7;
if(index%5==0)
{
Console.writeline(fivetotal);
fivetotal=0;
}
index++;
}

Answer 2

int i,j=0,s=0;
for(i=1;i<=1000,i++)
{if(i%7==0)
{if(++j<6,s=s+i;)
else(printf("%d",&s),j=1,s=i;)
}
}

Answer 3

int max = 0;
int y = 0;
for (int i = 1; i < 1000; i++)
{
if (i % 7 == 0)
{
y++;
max += i;
if (y % 5 == 0)
{
Console.WriteLine("count every five: " + max);
max = 0;
}
}
}