Question

求计算过程，请高手帮忙，，

Answer 1

 

追答

后面降幂吧，不写了

= (sin²x)³
= [(1 - cos2x)/2]³
= (1/8)(1 - 3cos2x + 3cos²2x - cos³2x)
= 1/8 - (3/8)cos2x + (3/8)[(1 + cos4x)/2] - (1/8)cos³2x
= ...
= 5/16 - (15/32)cos2x + (3/16)cos4x - (1/32)cos6x，之后积分