Question

python 字符串 赋值给list

怎么把字符串"['1.0','0.0','0.0','1.0']"变为list类型['1.0','0.0','0.0','1.0'],谢谢！
我从其他接口得到的是这样一个字符串，怎样把它直接转换为list呢？
“[['sh600275','武昌鱼','4.68','10.12','1','0.05','0','11.84'],['sz002105','信隆实业','11.06','10.05','1','18.01','0','7.12'],['sz300402','宝色股份','13.81','10.04','1','1','0','4.37'],['sh603169','兰石重装','5.70','10.04','1','0.58','0','3.45'],['sz002528','英飞拓','15.03','10.03','1','0.2','146.19','3.26']]”

Answer 1

import ast

x ="[['sh600275','武昌鱼','4.68','10.12','1','0.05','0','11.84'],['sz002105','信隆实业','11.06','10.05','1','18.01','0','7.12'],['sz300402','宝色股份','13.81','10.04','1','1','0','4.37'],['sh603169','兰石重装','5.70','10.04','1','0.58','0','3.45'],['sz002528','英飞拓','15.03','10.03','1','0.2','146.19','3.26']]"

x = ast.literal_eval(x)

print x

Answer 2

#coding: utf-8
import re
s = "['1.0','0.0','0.0','1.0']"
s = re.search('\[(.*)\]',s).group(1)
l = []
for x in  s.replace("'",'').split(','):
    try:
        l.append(float(x))
    except:
        pass
print l

 或者：

s = "['1.0','0.0','0.0','1.0']"
l= [float(x) for x in eval(s)]
print l