Question

数学计算题;前两个计算并化简，最后一个解方程

Answer 1

1.
=3x/(x-1)-[x/(x+1)]*[(x+1)(x-1)/2x]
=3x/(x-1)-[(x-1)/2]
=6x/2(x-1)-[(x-1)^2/2(x-1)]
=[6x-(x-1)^2]/2(x-1)
=-(x^2-8x+1)/(2x-2)
2
=m^2/(m-2)-[4/(m-2)]*[1/(m+2)]
=[m^2*(m-2)]/(m+2)-4/[(m-2)(m+2)]
=[m^3-2(m^2)-4]/(m^2-4)
3.
(x-3)/(x-2)+1=-3/(x-2)
左右两边同乘以（x-2）得
（x-3）+（x-2）=-3
2x-5=-3
2x=2
x=1
将x=1代入（x-2）=1-2=-1不等于0
所以原分式方程的解为x=1