Question

如何用sed或awk提取方括号中字符串

如何用简短的语句提取下面字符串中d的内容，
a=[asdfghjk],b=[],c=[],d=[asdfghjklkjhgfds1234sdfgh]

Answer 1

基本思路，先用逗号做分割，然后过滤出d=开头的字符串，清掉中括号，提取出里面的内容:

例如：

echo a=[asdfghjk],b=[],c=[],d=[asdfghjklkjhgfds1234sdfgh] | awk -F"," '{for (i=1;i<=NF;++i) print $i}' | awk 'gsub("d=","") {gsub("^\\[","",$0); gsub("\\]$",""); print $0}'