
求极限如图
3个回答
展开全部
(1)
|sinx+cosx|<=2
lim(x->∞ ) 1/(x^2+1) = 0
=>
lim(x->∞) ( sinx+cosx)/(x^2+1)
=0
(2)
let
y=3x
lim(x->0) (1-3x)^(2/x)
=lim(y->0) (1-y)^(6/y)
=e^(-6)
|sinx+cosx|<=2
lim(x->∞ ) 1/(x^2+1) = 0
=>
lim(x->∞) ( sinx+cosx)/(x^2+1)
=0
(2)
let
y=3x
lim(x->0) (1-3x)^(2/x)
=lim(y->0) (1-y)^(6/y)
=e^(-6)
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