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降幂再降幂
I = (1/4) ∫ (1+cos2x)^2 dx
= (1/4) ∫ [1+cos2x+(cos2x)^2] dx
= (1/4) ∫ (1+cos2x+1/2+cos4x) dx
= (1/4) ∫ (3/2+cos2x+cos4x) dx
= (1/4) [(3/2)x + (1/2)sin2x + (1/4)sin4x] + C
I = (1/4) ∫ (1+cos2x)^2 dx
= (1/4) ∫ [1+cos2x+(cos2x)^2] dx
= (1/4) ∫ (1+cos2x+1/2+cos4x) dx
= (1/4) ∫ (3/2+cos2x+cos4x) dx
= (1/4) [(3/2)x + (1/2)sin2x + (1/4)sin4x] + C
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ok知道了😂
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