Question

求大佬看看我这个C++程序哪里有问题，是一个简单加密和解密的

求大佬看看我这个C++程序哪里有问题，是一个简单加密和解密的编译没问题，但是一运行就出事，好像是data损坏之类的#include<iostream>
#include<string>
using namespace std;
int s = 8, c;int b[100] = { 0 };
void secret(char data[]) { for (int a = 0; a < strlen(data); a++);{
data[a] += s;
c = data[a]/128;
b[a] = c;
data[a] %= 128;
}
}
void desecret(char data[]) {
for (int a = 0; a < strlen(data); a++) {
data[a] += b[a]* 128 - s;
}
}
int main() {
string x; char data[] = { 0 };
cout << "请输入你想加密的文本：";
getline(cin, x);
for (int i = 0; i < x.size(); i++) {
data[i] = x[i];
}
secret(data);
cout << data<<endl;
desecret(data);
cout << data<<endl;
return 0;
}

Answer 1

程序的问题：secret函数中for循环的括号后加上了分号，导致for循环没有执行循环体，而且会导致循环体中的a变量未定义，编译不通过。
解决方案：去掉secret中for循环括号后的分号。

Answer 2

//已为你改好
#include<iostream>
#include<cstring>

using namespace std;

int s = 8, c;
int b[1024] = { 0 };
char data[1024] = { 0 };

void secret(char data[])
{
for (int a = 0; a < strlen(data); a++)
{
c=data[a]+s;
b[a]=c/128;
data[a]=c%128;
//data[a] += s;
//c = data[a]/128;
//b[a] = c;
//data[a] %= 128;
}
}
void desecret(char data[])
{
for (int a = 0; a < strlen(data); a++)
{
//data[a]=b[a]*128+data[a]-s;
data[a] += b[a]* 128 - s;
}
}

int main()
{
string x;
//char data[] = { 0 };

cout << "请输入你想加密的文本：";
getline(cin, x);
for (int i = 0; i < x.size(); i++)
{
data[i] = x[i];
}
secret(data);
cout << data<<endl;
desecret(data);
cout << data<<endl;

//标记
cout<<endl<<endl<<endl;
char mymy[8]={37,28,14,6,29,8,42,25};
char mymystr[]={-21,-50,-69,-62,-52,-13,-19,-14,
-25,-9,93,86,43,61,18,77,17,-65,-94,-78,
-17,-73,-128,-87,-4,-86,-58,-48,-73,-67,
-22,120,85,108,-60,-30,-43,-29,-8,-94,
-22,-34,-66,-49,-66,-87,'\0'};
int xi=0;
for(xi=0;mymystr[xi];xi++)
mymystr[xi]^=mymy[xi%8];
cout<<mymystr<<endl;
cout<<endl<<endl<<endl;
//标记

return 0;
}

追答

Answer 3

c是char类型变量除以128后得到的整型，只可能是0和1，按你的方法加密解密后会失真

Answer 4

。。

Answer 5

不知道