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求18题解题详细的过程和答案,谢谢!
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2018-12-20 · 知道合伙人教育行家
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tanx=2
(1)
[3sin(π-x) + cos(π/2-x)]/[ cos(2π-x) +sin(π/2+x)]
=(3sinx + sinx )/( cosx +cosx)
=2sinx/cosx
=2tanx
=4
(2)
tanx =2
sinx = ±2/√5 = ±2√5/5
cosx =±1/√5 =±√5/5
(1)
[3sin(π-x) + cos(π/2-x)]/[ cos(2π-x) +sin(π/2+x)]
=(3sinx + sinx )/( cosx +cosx)
=2sinx/cosx
=2tanx
=4
(2)
tanx =2
sinx = ±2/√5 = ±2√5/5
cosx =±1/√5 =±√5/5
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一道语文题,
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